2X^2+20x-750=0

Solution for 2X^2+20x-750=0 equation:

2X^2+20X-750=0

a = 2; b = 20; c = -750;
Δ = b2-4ac
Δ = 202-4·2·(-750)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-80}{2*2}=\frac{-100}{4}
=-25
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+80}{2*2}=\frac{60}{4}
=15
$